Comments on: Day 6: Going Into Hyperspace

By: 扶凯 » [Perl6]going-into-hyperspace 超运算符

扶凯 » [Perl6]going-into-hyperspace 超运算符 — Thu, 29 Sep 2011 16:30:23 +0000

[...] 本文为译文原作者 By colomon:http://perl6advent.wordpress.com/2009/12/06/day-6-going-into-hyperspace/ [...]

By: Joese

Joese — Sat, 27 Aug 2011 01:35:00 +0000

Thank you!

By: Ky6uk

Ky6uk — Tue, 16 Mar 2010 16:33:45 +0000

Good info. Thank you!

By: День 6: Входя в Гиперпространство | Ky6uk's Blog

День 6: Входя в Гиперпространство | Ky6uk's Blog — Tue, 16 Mar 2010 16:31:51 +0000

[...] Оригинальная статья. VN:F [1.8.5_1061]один момент…Rating: 0.0/10 (0 votes [...]

By: bened

bened — Mon, 07 Dec 2009 14:46:47 +0000

Ah, now I understand. Thanks! :)

By: colomon

colomon — Sun, 06 Dec 2009 23:40:41 +0000

BTW, I screwed up the >>++ example; just as you cannot say 3++, you cannot say (1, 2, 3, 4)>>++. However, you can do: [sourcecode light="true"] my @a = (1, 2, 3, 4); @a>>++; [/sourcecode] (I will try to edit the post to clean it up once the slashdotting is over.)

By: colomon

colomon — Sun, 06 Dec 2009 17:59:48 +0000

Because hyperoperators do not operate on the list in any set order. So if you say (1, 2, 3, 4)>>.say, it might respond 1 2 3 4 or it might respond 4 3 1 2 or 4 2 1 3. This is because Perl 6 implementations are allowed to optimize hyperoperators by reordering them and/or running them in parallel.

By: bened

bened — Sun, 06 Dec 2009 16:24:28 +0000

Thanks, the first part of this entry clarifies hyperoperators for me. The second part however I did not fully understand. Can you explain further why @a>>.say is not a good idea?