say (<a a a> Z <b b b> Z <c c c>).perl
# <a b c a b c a b c>

was giving a different result from:

say (<a b a b a b> Z <c c c>).perl
# <a c b c a c>

I found (after reading Synopse 3) that this is due to the fact that the
Z operator was list associative (not right or left). the zipping happens
all at once, rather than two at a time. The previous examples are actually
similar to the following (well, theres something wrong with the syntax):

say infix:<Z>(<a a a>; <b b b>; <c c c>).perl;
say infix:<Z>(<a b a b a b>, <c c c>).perl;

So its obvoius that the zip operator knows what to do with three operands.

my @a = <a>;
my @b = <b>;
my @c = ;
(@a Z @b Z @c).perl.say; # <a>

not equal to

(<a> Z @c).perl.say # <a>

It looks like perl6 has different array / array ref semantics.

@array.map: *.say;

versus

@array.map(*.say);

Both do the same thing, but the first looks more like natural language than the second. The same goes for

@array.map: { “$^a $^b”.say }

versus

@array.map({“$^a $^b”.say});

The Perl 6 language design is very nice, and the work being done with Rakudo, Parrot and Blizkost makes me excited for the future.

Second, [Z] apparently isn’t actually implemented yet in Rakudo.

I tried [Z] but got an error:
> my @a = 1, 2, 3; my @b = 4, 5, 6; my @c = @a, @b; say ([Z] @c).fmt;
Confused at line 1, near “@c).fmt;\n”
in Main (file , line )